(5x-9)/(x^2-x-6)=0

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Solution for (5x-9)/(x^2-x-6)=0 equation: 


D( x )

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

x in (-oo:-2) U (-2:3) U (3:+oo)

(5*x-9)/(x^2-x-6) = 0

x^2-x-6 = 0

x^2-x-6 = 0

DELTA = (-1)^2-(-6*1*4)

DELTA = 25

DELTA > 0

x = (25^(1/2)+1)/(1*2) or x = (1-25^(1/2))/(1*2)

x = 3 or x = -2

(x+2)*(x-3) = 0

(5*x-9)/((x+2)*(x-3)) = 0

5*x-9 = 0 // + 9

5*x = 9 // : 5

x = 9/5

x = 9/5

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